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/g/ Technology

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Anonymous 2016-01-23 18:36:03 No.52580898

[Missing image file: ]

I'd like to buy this product: http://www.acer.com/ac/en/GB/content/model/UM.HX3EE.001

Is there a way to know what are the dimensions (in centimeters) of the height and weight of the display?


>>
Anonymous 2016-01-23 18:36:58 No.52580913
Measure it

>>
Anonymous 2016-01-23 18:38:42 No.52580941
>>52580913
I don't have it. I'm planning to buy it.
So there's no way other than measure it, right?

>>
Anonymous 2016-01-23 19:04:17 No.52581272
>>52580898

from reichelt.de
>viewable screen size; 69 cm. viewable screen size; 27 Inch.

>>
Anonymous 2016-01-23 19:09:59 No.52581355
>>52580898

59.77cm × 33.62cm (23.53" × 13.24")

also learn math.

>>
Anonymous 2016-01-23 19:13:47 No.52581403
>>52580941
no, you can enlarge your penis, cut it 2x the sizes of the length. tape them together in a rectangle and there you have it

>>
Anonymous 2016-01-23 19:13:52 No.52581405
>>52580898

DPI too low.
Either go 23" 1080p or 27" 1440p.

>>
Anonymous 2016-01-23 19:14:58 No.52581429
>>52581355
learn math? I know the pitagora's theorem, man.
But I just have "d". How am I supposed to calc it?

>>
Anonymous 2016-01-23 19:15:52 No.52581441
>>52581429
16/9 or 4/3
You have all the information you need.

>>
Anonymous 2016-01-23 19:16:03 No.52581444
>>52581429

You also have a ratio of 16:9.

>>
Anonymous 2016-01-23 19:16:51 No.52581462
>>52581429
by not being stupid as fuck maybe

your question is like "how do i use google"

>>
Anonymous 2016-01-23 19:17:55 No.52581479
>>52581429

> learn math

It says right there.

>>
Anonymous 2016-01-23 19:18:13 No.52581485
>>52581444
Okay, I didn't take that into account. Thank you!
>>52581441
You could have been less "offensive", no?

>>
Anonymous 2016-01-23 19:18:40 No.52581494
>>52581429

>>
Anonymous 2016-01-23 19:19:18 No.52581507
To everyone who says learn math:
I didn't take into account the ratio.
OK?
>>52581501
I don't.

>>
Anonymous 2016-01-23 19:19:52 No.52581519
>>52581429
trigonometry nigga, sohcahtoa and all that sheeeit

>>
Anonymous 2016-01-23 19:20:43 No.52581525
>>52581507
If you really, actually, don't have an arts degree, you're an more of an embarrassment than is possible to put across in words. It would be slightly permissible if you did.

>>
Anonymous 2016-01-23 19:20:51 No.52581530
>>52581507
>I know math, I just don't know how to use it!

>>
Anonymous 2016-01-23 19:21:44 No.52581544
>>52581429
retard

>>
Anonymous 2016-01-23 19:22:01 No.52581546
>>52581530
clap clap.

>>
Anonymous 2016-01-23 19:24:29 No.52581587
>>52581405
where did you read the DPI info?

>>
Anonymous 2016-01-23 19:24:37 No.52581593
>>52581485
>You could have been less "offensive", no?
It's not offensive. It's didactic.

>>
Anonymous 2016-01-23 19:26:46 No.52581625
>>52580898

OK, if you promise to stop being a nigger in the future, I'll tell you how to do it.

Go here: sven.de/dpi
Put in 1920, 1080, 27 and get the dimensions and DPI.

>>
Anonymous 2016-01-23 19:31:54 No.52581704
>>52581587

First of all, I'm a glorious intellectual and not some retarded pleb.
Second, I didn't read it, I calculated it like you were supposed to do if you knew math.

>>
Anonymous 2016-01-23 19:38:20 No.52581811
Ok. I'll post my calcs, since you claim I'm a retard.


|c=27
-|c^2=a^2+b^2 => b=sqrt(c^2-a^2)
|a=b*9/16

a=sqrt(c^2-a^2)*9/16 => a^2=(c^2-a^2)*(9/16)^2 => a^2=c^2*(9/16)^2-a^2**(9/16)^2 =>
=> a^2+a^2*(9/16)^2=c^2*(9/16)^2 => a^2 [1+(9/16)^2]=c^2*(9/16)^2 =>
=> a^2 = c^2*(9/16)^2 / ([1+(9/16)^2]) => a = c*(9/16)/(sqrt(1+(9/16)^2))

a = 27*(9/16)/(sqrt(1+(9/16)^2)) = 13.2370534701 =>
=> b=sqrt(27^2-13.2370534701^2) = 23.5325395024

>>
Anonymous 2016-01-23 19:50:45 No.52581989
>>52581811

have a cookie.







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