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Anonymous 2014-01-29 20:10:47 No.6319422

[Missing image file: cards.jpg]

Q: You stand blindfolded in front of a table. you are told that there are 32 cards with the number up and an unknown amount of cards (so it's not sure it's 52) with the number down. Is there a possibility that you can divide the cards in two groups so that both groups have the same amount of cards with the number upwards.
Note: there is a chance that the answer is no, but that would be really stupid. It's a question from my gf school for 15 to 16 year olds


>>
Anonymous 2014-01-29 20:35:14 No.6319458
better formulation, because as it is now, your question is complete shit

>>
Anonymous 2014-01-29 20:44:38 No.6319476
>>6319458
I'll try to translate it better. still, maybe it's just a shitty question

>>
newt 2014-01-29 20:44:42 No.6319477
flip the first 32 cards.

these 32 cards now have the same number of face-up cards as there are on the rest of the table.

>>
Anonymous 2014-01-29 20:47:39 No.6319480
>>6319476
You stand blindfolded in front of a table on which there lay a lot of playing cards. You are told that 32 cards lay with the (i don't know how to say it, the side displayed in the picture)-side up and an unknown number with that side down.
Can you divide these cards in two groups so that there is an equal ammount of cards with the (pic)-side up, without taking of the blindfold

>>
Anonymous 2014-01-29 20:48:41 No.6319482
>>6319477
i don't think you know the difference between the first cards and the others, otherwise you could just divide those

>>
Anonymous 2014-01-29 20:50:19 No.6319486
>>6319480
lay face up vs face down

Without looking I think the answer is no.

>>
Anonymous 2014-01-29 20:51:57 No.6319491
>>6319486
me too. unless there is only one extra card







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